初中数学题

Suppose -o - 45 = -2s, 39 = -5s + o + 144. Suppose -19 + 5 = -2n + 3i, -4n + 4i = -s. Suppose -n = f - 5. Solve -11 - 9 = f*t for t.

Suppose -o - 45 = -2*s, 39 = -5*s + o + 144. Suppose -19 + 5 = -2*n + 3*i, -4*n + 4*i = -s. Suppose -n = f - 5. Solve -11 - 9 = f*t for t. -5 Suppose 11*l - 9*l - 34 = 0. Suppose -q - l = -4*a - 6,

初中数学题 2024-11-17 0 阅读

Let d be -1(2 + 4 + -6). Solve -2j - j - 6 = d for j.

Let d be -1*(2 + 4 + -6). Solve -2*j - j - 6 = d for j. -2 Let c(s) be the third derivative of -s 6 &frasl; 120 - s 5 &frasl; 20 + s 4 &frasl; 6 - 2*s 3 &frasl; 3 + 2*s**2. Let q be c(-4). Let l be

初中数学题 2024-11-17 0 阅读

Let k = -12 + 23. Suppose k = -2o + 27. Solve -4a = o + 8 for a.

Let k = -12 + 23. Suppose k = -2*o + 27. Solve -4*a = o + 8 for a. -4 Let s(d) = d 3 + 2*d 2 - 4*d. Let l be s(-3). Suppose -2*k + 3 = -k. Suppose -a + 2 = -l*p, -k*p + 4*a - 12 = a. Solve p = 2*h +

初中数学题 2024-11-17 0 阅读

Let u = -130 - -130. Solve 5 = -u*h + h for h.

Let u = -130 - -130. Solve 5 = -u*h + h for h. 5 Suppose 0*p + 20 = 5*p. Suppose 23 = -3*c + 50. Solve 11 + c = -p*b for b. -5 Let m(p) = p + 8. Let a be m(-5). Solve 3*o = -3 - a for o. -2 Let o =

初中数学题 2024-11-17 0 阅读

Let v(i) = i**2 - 5i + 2. Let p be v(5). Suppose 0 = -2h - px + 10, 4x - 2 = 3x. Solve 0n = -h*n for n.

Let v(i) = i**2 - 5*i + 2. Let p be v(5). Suppose 0 = -2*h - p*x + 10, 4*x - 2 = 3*x. Solve 0*n = -h*n for n. 0 Let t(m) = -5 - m**2 - 9*m - 7 + 4. Let v be t(-8). Let u be (-1)/4 + (-13)/(-4). Solve

初中数学题 2024-11-17 0 阅读

Let c = -15 + 22. Let v(d) = -d**2 + 7d + 4. Let s be v(c). Suppose -2o - 5 = -3r - 18, 4o - s*r - 20 = 0. Solve -b + o - 7 = 0 for b.

Let c = -15 + 22. Let v(d) = -d**2 + 7*d + 4. Let s be v©. Suppose -2*o - 5 = -3*r - 18, 4*o - s*r - 20 = 0. Solve -b + o - 7 = 0 for b. -5 Let h(y) = 4*y + 4. Let o be h(-1). Solve o*v = -5*v

初中数学题 2024-11-17 0 阅读

Let a(h) be the third derivative of -h6/120 - h5/15 - h4/24 - h3/6 - 3*h**2. Let s be a(-4). Solve -3t = -4t + s for t.

Let a(h) be the third derivative of -h 6 &frasl; 120 - h 5 &frasl; 15 - h 4 &frasl; 24 - h 3 &frasl; 6 - 3*h**2. Let s be a(-4). Solve -3*t = -4*t + s for t. 3 Let m be 174/(-8) + 2/(-8). Let u be

初中数学题 2024-11-17 0 阅读

Suppose 3o + 0o = 0. Solve 4 = -4l - ol for l.

Suppose -10 + 45 = 7r. Solve -rz + 3 = 13 for z.

Suppose 4q + 3c = -12, 5c + 5 = 4q - 15. Solve -3*w - w = q for w.

Suppose -o - 45 = -2s, 39 = -5s + o + 144. Suppose -19 + 5 = -2n + 3i, -4n + 4i = -s. Suppose -n = f - 5. Solve -11 - 9 = f*t for t.

Let d be -1(2 + 4 + -6). Solve -2j - j - 6 = d for j.

Let k = -12 + 23. Suppose k = -2o + 27. Solve -4a = o + 8 for a.

Let u = -130 - -130. Solve 5 = -u*h + h for h.

Let v(i) = i**2 - 5i + 2. Let p be v(5). Suppose 0 = -2h - px + 10, 4x - 2 = 3x. Solve 0n = -h*n for n.

Let c = -15 + 22. Let v(d) = -d**2 + 7d + 4. Let s be v(c). Suppose -2o - 5 = -3r - 18, 4o - s*r - 20 = 0. Solve -b + o - 7 = 0 for b.

Let a(h) be the third derivative of -h6/120 - h5/15 - h4/24 - h3/6 - 3*h**2. Let s be a(-4). Solve -3t = -4t + s for t.

小学数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.654.36+6.643.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Suppose 3*o + 0*o = 0. Solve 4 = -4*l - o*l for l.

Suppose -10 + 45 = 7*r. Solve -r*z + 3 = 13 for z.

Suppose 4*q + 3*c = -12, 5*c + 5 = 4*q - 15. Solve -3*w - w = q for w.

Suppose -o - 45 = -2*s, 39 = -5*s + o + 144. Suppose -19 + 5 = -2*n + 3*i, -4*n + 4*i = -s. Suppose -n = f - 5. Solve -11 - 9 = f*t for t.

Let d be -1*(2 + 4 + -6). Solve -2*j - j - 6 = d for j.

Let k = -12 + 23. Suppose k = -2*o + 27. Solve -4*a = o + 8 for a.

Let u = -130 - -130. Solve 5 = -u*h + h for h.

Let v(i) = i**2 - 5*i + 2. Let p be v(5). Suppose 0 = -2*h - p*x + 10, 4*x - 2 = 3*x. Solve 0*n = -h*n for n.

Let c = -15 + 22. Let v(d) = -d**2 + 7*d + 4. Let s be v(c). Suppose -2*o - 5 = -3*r - 18, 4*o - s*r - 20 = 0. Solve -b + o - 7 = 0 for b.

Let a(h) be the third derivative of -h**6/120 - h**5/15 - h**4/24 - h**3/6 - 3*h**2. Let s be a(-4). Solve -3*t = -4*t + s for t.

小学数学题

初中数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.65*4.36+6.64*3.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Suppose 3o + 0o = 0. Solve 4 = -4l - ol for l.

Suppose -10 + 45 = 7r. Solve -rz + 3 = 13 for z.

Suppose 4q + 3c = -12, 5c + 5 = 4q - 15. Solve -3*w - w = q for w.

Suppose -o - 45 = -2s, 39 = -5s + o + 144. Suppose -19 + 5 = -2n + 3i, -4n + 4i = -s. Suppose -n = f - 5. Solve -11 - 9 = f*t for t.

Let d be -1(2 + 4 + -6). Solve -2j - j - 6 = d for j.

Let k = -12 + 23. Suppose k = -2o + 27. Solve -4a = o + 8 for a.

Let v(i) = i**2 - 5i + 2. Let p be v(5). Suppose 0 = -2h - px + 10, 4x - 2 = 3x. Solve 0n = -h*n for n.

Let c = -15 + 22. Let v(d) = -d**2 + 7d + 4. Let s be v(c). Suppose -2o - 5 = -3r - 18, 4o - s*r - 20 = 0. Solve -b + o - 7 = 0 for b.

Let a(h) be the third derivative of -h6/120 - h5/15 - h4/24 - h3/6 - 3*h**2. Let s be a(-4). Solve -3t = -4t + s for t.

3.654.36+6.643.65-3.65．