初中数学题

Let j = -17 - -20. Let t(p) = -2p - 6. Let l be t(-4). Solve 0 = z - lz - j for z.

Let j = -17 - -20. Let t(p) = -2*p - 6. Let l be t(-4). Solve 0 = z - l*z - j for z. -3 Let i(z) = -z 3 - 8*z 2 + 9*z + 8. Let n be i(-9). Let x(u) = -u**2 + 8*u. Let c be x(n). Solve c = -2*m - 5 +

初中数学题 2024-11-17 0 阅读

Let m(v) = -v**2 - 9v - 13. Let c be m(-6). Solve 3h - 17 = -c for h.

Let m(v) = -v**2 - 9*v - 13. Let c be m(-6). Solve 3*h - 17 = -c for h. 4 Suppose -2*q - 4*q = 11*q. Solve 3*h = -q*h + 3 for h. 1 Suppose -5*z + 3*z + 46 = 0. Solve -z + 3 = -4*t for t. 5 Suppose

初中数学题 2024-11-17 0 阅读

Let w be 4/10 - 56/(-10). Suppose 18 = 3g + w. Suppose 0x - 32 = -5s - gx, -4s + 31 = 5x. Solve 0 - s = y for y.

Let w be 4 &frasl; 10 - 56/(-10). Suppose 18 = 3*g + w. Suppose 0*x - 32 = -5*s - g*x, -4*s + 31 = 5*x. Solve 0 - s = y for y. -4 Let y be (-11)/(-3) - (-20)/60. Solve k - 5*k = y for k. -1 Let l be

初中数学题 2024-11-17 0 阅读

Let v = -7 - -3. Let k be v/((-24)/(-9))2. Let p = 6 + k. Solve 2b + p*b = -15 for b.

Let v = -7 - -3. Let k be v/((-24)/(-9))*2. Let p = 6 + k. Solve 2*b + p*b = -15 for b. -3 Let f be -2 + 10* 3 &frasl; 6 . Let w = f + -2. Solve y - 2 = w for y. 3 Suppose 2*r - r - 10 = -i, -5*i +

初中数学题 2024-11-17 0 阅读

Suppose 2 = g - 0. Suppose gh + 2h + 3 = z, h = z - 3. Solve 3*s - s - 4 = h for s.

Suppose 2 = g - 0. Suppose g*h + 2*h + 3 = z, h = z - 3. Solve 3*s - s - 4 = h for s. 2 Suppose -2*b + 8 = -y, 3*b - 4*y - 11 = 11. Solve 5*x = b*x for x. 0 Suppose 5*b - 3*v = 29, 3 = 2*b + 3*v + 4.

初中数学题 2024-11-17 0 阅读

Let i = 5 + -3. Suppose ig + 0g - 14 = 0. Solve 0 = -gf + 4f for f.

Let i = 5 + -3. Suppose i*g + 0*g - 14 = 0. Solve 0 = -g*f + 4*f for f. 0 Suppose -18*s + 6 = -16*s. Suppose -4*r = -s*q - 23, 4*r = q - 6*q - 17. Solve -g - g = -r for g. 1 Let s(t) = -t 3 + 7*t 2 +

初中数学题 2024-11-17 0 阅读

Suppose 0g = -g. Suppose gn = n. Let f be 2/(60/(-18) + 4). Solve t = -n - f for t.

Suppose 0*g = -g. Suppose g*n = n. Let f be 2/(60/(-18) + 4). Solve t = -n - f for t. -3 Let m(o) = o - 9. Let p be m(7). Let n = p + 5. Suppose 2*g - 2 - 6 = n*a, -12 = -3*g - 2*a. Solve -12 = g*t -

初中数学题 2024-11-17 0 阅读

Let k(z) = 9z - 14. Let r be k(2). Solve 35 = rm + 15 for m.

Suppose -20 = 2t - 4t - q, -t - 4q - 4 = 0. Solve 0 = 2r + r - t for r.

Suppose 3x = -4x + 35. Solve -9c - x = -8c for c.

Let j = -17 - -20. Let t(p) = -2p - 6. Let l be t(-4). Solve 0 = z - lz - j for z.

Let m(v) = -v**2 - 9v - 13. Let c be m(-6). Solve 3h - 17 = -c for h.

Let w be 4/10 - 56/(-10). Suppose 18 = 3g + w. Suppose 0x - 32 = -5s - gx, -4s + 31 = 5x. Solve 0 - s = y for y.

Let v = -7 - -3. Let k be v/((-24)/(-9))2. Let p = 6 + k. Solve 2b + p*b = -15 for b.

Suppose 2 = g - 0. Suppose gh + 2h + 3 = z, h = z - 3. Solve 3*s - s - 4 = h for s.

Let i = 5 + -3. Suppose ig + 0g - 14 = 0. Solve 0 = -gf + 4f for f.

Suppose 0g = -g. Suppose gn = n. Let f be 2/(60/(-18) + 4). Solve t = -n - f for t.

小学数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.654.36+6.643.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Let k(z) = 9*z - 14. Let r be k(2). Solve 35 = r*m + 15 for m.

Suppose -20 = 2*t - 4*t - q, -t - 4*q - 4 = 0. Solve 0 = 2*r + r - t for r.

Suppose 3*x = -4*x + 35. Solve -9*c - x = -8*c for c.

Let j = -17 - -20. Let t(p) = -2*p - 6. Let l be t(-4). Solve 0 = z - l*z - j for z.

Let m(v) = -v**2 - 9*v - 13. Let c be m(-6). Solve 3*h - 17 = -c for h.

Let w be 4/10 - 56/(-10). Suppose 18 = 3*g + w. Suppose 0*x - 32 = -5*s - g*x, -4*s + 31 = 5*x. Solve 0 - s = y for y.

Let v = -7 - -3. Let k be v/((-24)/(-9))*2. Let p = 6 + k. Solve 2*b + p*b = -15 for b.

Suppose 2 = g - 0. Suppose g*h + 2*h + 3 = z, h = z - 3. Solve 3*s - s - 4 = h for s.

Let i = 5 + -3. Suppose i*g + 0*g - 14 = 0. Solve 0 = -g*f + 4*f for f.

Suppose 0*g = -g. Suppose g*n = n. Let f be 2/(60/(-18) + 4). Solve t = -n - f for t.

小学数学题

初中数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.65*4.36+6.64*3.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Let k(z) = 9z - 14. Let r be k(2). Solve 35 = rm + 15 for m.

Suppose -20 = 2t - 4t - q, -t - 4q - 4 = 0. Solve 0 = 2r + r - t for r.

Suppose 3x = -4x + 35. Solve -9c - x = -8c for c.

Let j = -17 - -20. Let t(p) = -2p - 6. Let l be t(-4). Solve 0 = z - lz - j for z.

Let m(v) = -v**2 - 9v - 13. Let c be m(-6). Solve 3h - 17 = -c for h.

Let w be 4/10 - 56/(-10). Suppose 18 = 3g + w. Suppose 0x - 32 = -5s - gx, -4s + 31 = 5x. Solve 0 - s = y for y.

Let v = -7 - -3. Let k be v/((-24)/(-9))2. Let p = 6 + k. Solve 2b + p*b = -15 for b.

Suppose 2 = g - 0. Suppose gh + 2h + 3 = z, h = z - 3. Solve 3*s - s - 4 = h for s.

Let i = 5 + -3. Suppose ig + 0g - 14 = 0. Solve 0 = -gf + 4f for f.

Suppose 0g = -g. Suppose gn = n. Let f be 2/(60/(-18) + 4). Solve t = -n - f for t.

3.654.36+6.643.65-3.65．