初中数学题

Suppose -2r + 18 = -i, 0 = 5r + 4i - 13 - 6. Solve -8 - r = 3z for z.

Suppose -2*r + 18 = -i, 0 = 5*r + 4*i - 13 - 6. Solve -8 - r = 3*z for z. -5 Let o(h) be the first derivative of -h** 2 &frasl; 2 + 8*h - 2. Suppose -2*u = -9 - 3. Let i be o(u). Solve -i*t = -3 + 5

初中数学题 2024-11-16 0 阅读

Suppose 3u + 3q - 27 = 0, -4u + 5q + 10 = 1. Suppose -3a + ua = 0. Solve 3*c - c + 2 = a for c.

Suppose 3*u + 3*q - 27 = 0, -4*u + 5*q + 10 = 1. Suppose -3*a + u*a = 0. Solve 3*c - c + 2 = a for c. -1 Let o(j) be the first derivative of j 4 &frasl; 4 - 5*j 3 &frasl; 3 - 3*j**2 + 3*j + 2. Let f

初中数学题 2024-11-16 0 阅读

Suppose 63 = 2o + o. Suppose 7g - o = 4g. Let j be 3/(-3) - -16 - 2. Solve g + j = -4d for d.

Suppose 63 = 2*o + o. Suppose 7*g - o = 4*g. Let j be 3/(-3) - -16 - 2. Solve g + j = -4*d for d. -5 Let z be (6/(-12))/((-1)/32). Solve -6*g = -2*g - z for g. 4 Let j be 3 - 4/(-16)*0. Let g(m) be

初中数学题 2024-11-16 0 阅读

Suppose 0 = -u + 4u - 3o - 3, 2u + o = 8. Let l(h) = 4h**3 - 2*h**2 + h. Let g be l(1). Solve -g = u*j + 12 for j.

Suppose 0 = -u + 4*u - 3*o - 3, 2*u + o = 8. Let l(h) = 4*h 3 - 2*h 2 + h. Let g be l(1). Solve -g = u*j + 12 for j. -5 Let j(a) = a + 4. Let y be j(2). Let b = 11 - y. Solve b*x = x for x. 0 Suppose

初中数学题 2024-11-16 0 阅读

Suppose 3a - 35 = 8a. Let f = -6 - a. Solve -3*m + 8 = -f for m.

Suppose 3*a - 35 = 8*a. Let f = -6 - a. Solve -3*m + 8 = -f for m. 3 Suppose 7*s = s. Solve s = -a + 2*a for a. 0 Let r(b) = -3 + b + b 3 - 5*b - 2*b 2 + b. Let v be r(3). Let q be (-11)/v + (-8)/12.

初中数学题 2024-11-16 0 阅读

Let r = 9 - 5. Let k = r - 0. Suppose -f - 3 = 0, kf + 12 = -5y + 6y. Solve 0 = -3p - 12 - y for p.

Let r = 9 - 5. Let k = r - 0. Suppose -f - 3 = 0, k*f + 12 = -5*y + 6*y. Solve 0 = -3*p - 12 - y for p. -4 Let v = -97 - -97. Solve -5*n + 14 + 11 = v for n. 5 Let h be (-2)/(-3) - (-19)/3. Suppose 0

初中数学题 2024-11-16 0 阅读

Let s be (-3 + 4 + -6)-1. Solve 2v + s = -3*v for v.

Let s be (-3 + 4 + -6)*-1. Solve 2*v + s = -3*v for v. -1 Let l be (-2 + 2)/(0 + 1). Solve l*b - 2*b = 0 for b. 0 Suppose d + d = 0. Solve -t + d*t = 0 for t. 0 Let r = -10 - -12. Suppose -3*o - 6*x

初中数学题 2024-11-16 0 阅读

Suppose -5 = -4u + 3. Let j(m) = -3m**2 - 3m2 - 6 - mu - 2m - m**3. Let d be j(-7). Solve dt - 12 = 4t for t.

Suppose -5 = -4*u + 3. Let j(m) = -3*m 2 - 3*m 2 - 6 - m u - 2*m - m 3. Let d be j(-7). Solve d*t - 12 = 4*t for t. 3 Suppose -25 = -5*b + 15. Solve 0 = -2*t + b for t. 4 Suppose -q + 6 = -0. Let

初中数学题 2024-11-16 0 阅读

Let z(o) = 2*o**2. Let g be z(-1). Suppose -3a = -gc + 17, 3a = -c + 4c - 24. Solve -5 = -3*s + c for s.

Let z(o) = 2*o**2. Let g be z(-1). Suppose -3*a = -g*c + 17, 3*a = -c + 4*c - 24. Solve -5 = -3*s + c for s. 4 Suppose 2*h + 2*h - 27 = 5*y, 2*h - 3*y = 15. Suppose -k + h = -4*v, 3 = -5*v - 2*k + 9.

初中数学题 2024-11-16 0 阅读

Let b = -4 - -6. Solve -j + 1 = b for j.

Let b = -4 - -6. Solve -j + 1 = b for j. -1 Let f = 28 - 26. Solve -5*c = -f*c - 15 for c. 5 Suppose 0 + 5 = -5*b. Let o = b - -3. Solve 0*m = -o*m - 2 for m. -1 Let c(j) = j**2 - 6*j + 6. Let f be

初中数学题 2024-11-16 0 阅读

Suppose -2r + 18 = -i, 0 = 5r + 4i - 13 - 6. Solve -8 - r = 3z for z.

Suppose 3u + 3q - 27 = 0, -4u + 5q + 10 = 1. Suppose -3a + ua = 0. Solve 3*c - c + 2 = a for c.

Suppose 63 = 2o + o. Suppose 7g - o = 4g. Let j be 3/(-3) - -16 - 2. Solve g + j = -4d for d.

Suppose 0 = -u + 4u - 3o - 3, 2u + o = 8. Let l(h) = 4h**3 - 2*h**2 + h. Let g be l(1). Solve -g = u*j + 12 for j.

Suppose 3a - 35 = 8a. Let f = -6 - a. Solve -3*m + 8 = -f for m.

Let r = 9 - 5. Let k = r - 0. Suppose -f - 3 = 0, kf + 12 = -5y + 6y. Solve 0 = -3p - 12 - y for p.

Let s be (-3 + 4 + -6)-1. Solve 2v + s = -3*v for v.

Suppose -5 = -4u + 3. Let j(m) = -3m**2 - 3m2 - 6 - mu - 2m - m**3. Let d be j(-7). Solve dt - 12 = 4t for t.

Let z(o) = 2*o**2. Let g be z(-1). Suppose -3a = -gc + 17, 3a = -c + 4c - 24. Solve -5 = -3*s + c for s.

Let b = -4 - -6. Solve -j + 1 = b for j.

小学数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.654.36+6.643.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Suppose -2*r + 18 = -i, 0 = 5*r + 4*i - 13 - 6. Solve -8 - r = 3*z for z.

Suppose 3*u + 3*q - 27 = 0, -4*u + 5*q + 10 = 1. Suppose -3*a + u*a = 0. Solve 3*c - c + 2 = a for c.

Suppose 63 = 2*o + o. Suppose 7*g - o = 4*g. Let j be 3/(-3) - -16 - 2. Solve g + j = -4*d for d.

Suppose 0 = -u + 4*u - 3*o - 3, 2*u + o = 8. Let l(h) = 4*h**3 - 2*h**2 + h. Let g be l(1). Solve -g = u*j + 12 for j.

Suppose 3*a - 35 = 8*a. Let f = -6 - a. Solve -3*m + 8 = -f for m.

Let r = 9 - 5. Let k = r - 0. Suppose -f - 3 = 0, k*f + 12 = -5*y + 6*y. Solve 0 = -3*p - 12 - y for p.

Let s be (-3 + 4 + -6)*-1. Solve 2*v + s = -3*v for v.

Suppose -5 = -4*u + 3. Let j(m) = -3*m**2 - 3*m**2 - 6 - m**u - 2*m - m**3. Let d be j(-7). Solve d*t - 12 = 4*t for t.

Let z(o) = 2*o**2. Let g be z(-1). Suppose -3*a = -g*c + 17, 3*a = -c + 4*c - 24. Solve -5 = -3*s + c for s.

Let b = -4 - -6. Solve -j + 1 = b for j.

小学数学题

初中数学题

高中数学题

大学高等数学

画室

一个长方体的底面是周长16cm的正方形，高3cm，这个长方体的体积是多少立方厘米？

吴老师把35支铅笔和40本练习本分别平均奖给几个三好学生，结果练习本差2本，铅笔正好．这个班级的三好学生最多有多少人？

四2班学生年龄分布的情况是：13岁的有3人，12岁的有15人，11岁的有11人，10岁的有21人．这个班的平均年龄是多少岁？

3.65*4.36+6.64*3.65-3.65．

两个因数的积是15.6，一个因数是0.8，另一个因数是多少．

一个直角三角形的周长是90厘米，三条边长之比是13：12：5，它的面积是多少平方厘米．

Suppose -2r + 18 = -i, 0 = 5r + 4i - 13 - 6. Solve -8 - r = 3z for z.

Suppose 3u + 3q - 27 = 0, -4u + 5q + 10 = 1. Suppose -3a + ua = 0. Solve 3*c - c + 2 = a for c.

Suppose 63 = 2o + o. Suppose 7g - o = 4g. Let j be 3/(-3) - -16 - 2. Solve g + j = -4d for d.

Suppose 0 = -u + 4u - 3o - 3, 2u + o = 8. Let l(h) = 4h**3 - 2*h**2 + h. Let g be l(1). Solve -g = u*j + 12 for j.

Suppose 3a - 35 = 8a. Let f = -6 - a. Solve -3*m + 8 = -f for m.

Let r = 9 - 5. Let k = r - 0. Suppose -f - 3 = 0, kf + 12 = -5y + 6y. Solve 0 = -3p - 12 - y for p.

Let s be (-3 + 4 + -6)-1. Solve 2v + s = -3*v for v.

Suppose -5 = -4u + 3. Let j(m) = -3m**2 - 3m2 - 6 - mu - 2m - m**3. Let d be j(-7). Solve dt - 12 = 4t for t.

Let z(o) = 2*o**2. Let g be z(-1). Suppose -3a = -gc + 17, 3a = -c + 4c - 24. Solve -5 = -3*s + c for s.

3.654.36+6.643.65-3.65．